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3-27
u Maximum Value
K4(CALC)6(g)2(FMax) f (x), a , b , n !/( ) )
(
a: start point of interval, b: end point of interval, n: precision ( n = 1 to 9))
Example To determine the minimum value for the interval defined by start
point
a = 0 and end point b = 3, with a precision of n = 6 for the function
y = x
2
– 4 x + 9
Input
f (x).
AK4(CALC)6(g)1(FMin)a5(U-Z)4(X)x-e4(X)
+j,
Input the interval
a = 0, b = 3.
a,d,
Input the precision
n = 6.
g!/( ) )w
• In the function
f (x), only X can be used as a variable in expressions. Other variables (A
through Z excluding X, r, Ƨ) are treated as constants, and the value currently assigned to
that variable is applied during the calculation.
• Input of
n and the closing parenthesis can be omitted.
• Discontinuous points or sections with drastic fluctuation can adversely affect precision or
even cause an error.
• Inputting a larger value for
n increases the precision of the calculation, but it also increases
the amount of time required to perform the calculation.
• The value you input for the end point of the interval (
b) must be greater than the value you
input for the start point ( a). Otherwise an error occurs.
• You can interrupt an ongoing maximum/minimum calculation by pressing the A key.
• You can input an integer in the range of 1 to 9 for the value of
n. Using any value outside this
range causes an error.
• You cannot use a differential, quadratic differential, integration, Σ , maximum/minimum value,
Solve, RndFix or log
a
b calculation expression inside of a maximum/minimum calculation
term.
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