Weil-McLain EVERGREEN PRO EVG-399 Gas Boiler Evergreen High Efficiency Gas Boiler

User Manual - Page 40

For EVERGREEN PRO EVG-399.

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Part number 550-100-211/0122
– 40 –

All piping methods shown in this manual use
primary/secondary connection to the boiler loop.
These designs ensure proper flow through the
boiler, for the most ecient and reliable operation
of the boiler and the heating system. For other
piping methods, consult your local Weil-McLain
representative or see separate boiler piping guides.

e boiler circulator (Taco 0014 for Evergreen
®
220, 299 and
300; Taco 0013 for Evergreen
®
399) is shipped loose. Locate it
in the boiler outlet, as shown in the appropriate piping diagram
in this manual.
DONOT use the boiler circulator in any location
other than the ones shown in this manual. e
boiler circulator is selected to ensure adequate ow
through the boiler.
Failure to comply could result in unreliable perfor-
mance and nuisance shut downs from insucient ow.


Install a system circulator or zone circulators as shown in the
piping diagrams in this manual. ese circulators must be sup-
plied by the installer.
Systemorzonecirculatorowrate
1. Size circulators based on the ow rate required to achieve the
temperature change needed.
2. You can closely estimate temperature rise (or drop) through a
circuit by using the following formula, where TD is tempera-
ture rise (or drop), FLOW is ow rate (in gpm), and BTUH
is the heat load for the circuit:
FLOW =
BTUH
—–—–—–—–
TDx500
Example:
Consider a system loop for a system with total heating load equal
to 210,000 Btuh. e desired temperature drop through the sys-
tem piping is 20°F. en the required ow rate is:
FLOW =
210,000
—–—–—–—–
20x500
= 21gpm
SIMPLIFIED:
For20°temperaturedrop,FLOW=MBH/10.
Systemorzonecirculatorheadrequirement
1. e circulator must be capable of delivering the required ow
against the head loss that will occur in the piping.
2. Determine the pipe size needed and the resultant head loss
using accepted engineering methods.
3. e simplied pipe sizing here is limited to residential sys-
tems, and does not include systems with fan coil units or
radiant tubing.
The following simplified method for pipe and
circulator sizing must be limited to residential ap-
plications using baseboard (nned or cast iron),
cast iron radiators or convectors. DO NOT apply
for radiant heating, fan coil units or commercial
installations.

1. Install the boiler and piping using the recommended piping
layouts shown in this manual.
2. Size the piping and components for each circuit in the space
heating system using Figure49,page41.
Attheowrates
listed, the head loss in all piping will be 0.04 feet per
footofpipe.
a. Det
ermine the heating load (Btuh) for each circuit.
b. Calculate the ow rate for each circuit using its load.
c. To use a 20°F temperature drop, just divide the
MBH (1,000’s of Btuh) by 10.
d. Example — Flow for 20°F temp drop with 35,000 Btuh:
FLOW = 35MBH / 10 = 3.5 gpm
e. Find the pipe size in Figure49,page41 that has a max
ow rate just larger than that required for the circuit.
f. Find the total equivalent length (TEL) of the circuit.
g. TEL accounts for losses through ttings and valves by
using the equivalent length of pipe that would cause the
same head loss. Add these numbers to the measured
length of the circuit to nd TEL in feet.
h.
TELisusuallycloseto1.5timesthelengthofthe
circuitforresidentialbaseboard,radiatororcon-
vectorapplications.
i. Measure the length of each circuit from the circulator
outlet back to its inlet. en multiply this length times
1.5 to get the approximate TEL of the circuit.
j. Find the head loss for
each circuit:
TEL=1.5XCircuitLength
(feet)
HEAD=TELX0.04
(feet water column)
k. NOTE: Size system header piping for the total ow of all
connected zones.
3. Example:
a. For a circuit with heating load = 45,000 Btuh (= 45 MBH).
Measured length of circuit is 88 feet.
b. Flow = 45 MBH / 10 = 4.5 gpm.
c. TEL = 1.5 x 88 feet = 132 feet.
d. From Figure49,page41, select 1" pipe (max ow = 7.1
gpm).
e. Head loss = TEL x 0.04 = 132 x 0.04 = 5.28 feet.
f. Select a circulator that can deliver at least 4.5gpm at a
head of 5.28feet. (Read the NOTICE below.)
To use this method, limit the ow through ¾"
nned-tube baseboard to 3.9 gpm, or use 1" base-
board and limit ow to 7.1 gpm. If the total load of
the circuit requires more ow, split the circuit into
two or more.
 (continued)
220 /29 9/3 00 /39 9 
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