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84
W415-1361 / 11.28.14
FR
90°
V
1
V
2
H
1
H
2
90°
90°
H
3
45°
18.2_3A
Exemple :
V
1
= 1,5 PI (0,5m)
V
2
= 5 PI (1,5m)
V
T
= V
1
+ V
2
= 1,5PI (0,5m) + 5PI (1,5m) = 6,5 PI (2m)
H
1
= 1 PI (0,3m)
H
2
= 1 PI (0,3m)
H
3
= 10,75 PI (3,3m)
H
R
= H
1
+ H
2
+ H
3
= 1PI (0,3m) + 1PI (0,3m) + 10,75PI (3,3m) = 12,75PI (3,9m)
H
O
= 0,03 (quatre coudes 90° + un coude 45° - 90°)
= 0,03 (360° + 45° - 90°) = 6,75 PI (2,1m)
H
T
= H
R
+ H
O
= 12,75PI (3,9m) + 6,75PI (2,1m) = 19,5PI (5,9m)
H
T
+ V
T
= 19,5 PI (5,9m) + 6,5 PI (2m) = 26 PI (7,9m)
Formule 1 :
H
T
< 3 V
T
3 V
T
= 3PI (0,9m) x 6,5PI (2m) = 19,5PI (5,9m)
19,5 PI (5,9m) = 19,5 PI (5,9m)
Formule 2 :
H
T
+ V
T
< 40 PI (12,2m)
26 PI (7,9m) < 40 PI (12,2m)
Puisque les deux formules sont respectées, cette configuration d'évacuation est acceptable.
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