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20
W415-1361 / 11.28.14
EN
90°
V
1
V
2
H
1
H
2
90°
90°
H
3
45°
18.2_3A
Example:
V
1
= 1.5 FT (0.5m)
V
2
= 5 FT (1.5m)
V
T
= V
1
+ V
2
= 1.5FT (0.5m)+ 5FT (1.5m) = 6.5 FT (2m)
H
1
= 1 FT (0.3m)
H
2
= 1 FT (0.3m)
H
3
= 10.75 FT (3.3m)
H
R
= H
1
+ H
2
+ H
3
= 1FT (0.3m) + 1FT (0.3m) + 10.75FT (3.3m) = 12.75FT (3.9m)
H
O
= .03 (four 90° elbows + one 45° elbow - 90°)
= .03 (360° + 45° - 90°) = 6.75 FT (2.1m)
H
T
= H
R
+ H
O
= 12.75FT (3.9m) + 6.75FT (2.1m) = 19.5 FT (5.9m)
H
T
+ V
T
= 19.5FT (5.9m) + 6.5FT (2m) = 26 FT (7.9m)
Formula 1:
H
T
< 3 V
T
3 V
T
= 3FT (0.9m) x 6.5FT (2m) = 19.5FT (5.9m)
19.5FT (5.9m) = 19.5FT (5.9m)
Formula 2:
H
T
+ V
T
< 40 FT (12.2m)
26 FT (7.9m) < 40 FT (12.2m)
Since both formulas are met, this vent configuration is acceptable.
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