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38 Outside Unit
Calculation of amount of refrigerant
Refrigerant piping system
The calculation of the additional charge should take into account the length of pipe.
If a negative result is obtained from
the calculation, no refrigerant needs
to be added.
CAUTION
Additional charge (kg)
Product charge(1unit)(kg)
=
+
+
+
+
+
+=
+
Total liquid pipe (m): Ø22.2mm
x 0.354(kg/m)
x 0.266(kg/m)
x 0.173(kg/m)
x 0.118(kg/m)
x 0.061(kg/m)
x 0.022(kg/m)
Total liquid pipe (m): Ø19.05mm
Total liquid pipe (m): Ø15.88mm
Total liquid pipe (m): Ø12.7mm
Total liquid pipe (m): Ø9.52mm
Total liquid pipe (m): Ø6.35mm
+
x 0.5 kg
Number of installed HR units
CF(kg) (Correction factor)
Total amount(kg)
A
A B
B
Outside unit
Header branch
Indoor unit
Ex) 10HP
Additional Charge = A x 0.041 + B x 0.041 + C x 0.041
+ D x 0.041 + E x 0.015 + HR + CF
= 164 x 0.041 + 33 x 0.041 + 33 x 0.041
+ 33 x 0.041 + 33 x 0.015 + 0(CF)
= 11.3lbs(5.1kg)
A : Ø9.52(3/8), 50m(164ft)
B : Ø9.52(3/8), 10m(33ft)
C : Ø9.52(3/8), 10m(33ft)
D : Ø9.52(3/8), 10m(33ft)
E : Ø 6.35(1/4), 10m(33ft)
u Special condition 1
In case of the No. of CST TQ/RAC SE/ARTCOOL SF models are over than 50% of the connected
indoor units when the total No. of connected indoor units are over than 50% of the max. connectable
indoor units.
n Additional refrigerant charging amount (kg(lbs)) : Ⓒ
= (A x
α+ B x ß) - (AVG x ß)
• A = Total No. of TQ, SE and SF Indoor units,
α= 0.5
• B = Total No. of except TQ, SE and SF Indoor units, ß = 0.3
• AVG = 50% of Max. No. of connectable Indoor units.
Example)
1) Installation Information
- Outside unit : 10HP
- Total indoor units : 6 units (TQ 3 units, SE 2 units, BH 1 unit)
2) Information from PDB
- Max. No. of connectable indoor units : 16 units
- Calculated additional refrigerant amount = 2kg (4.41lbs) : Ⓑ
3) Indoor refrigerant charging amount
= (5 units x 0.5+1 unit x 0.3) - (8 units x 0.3) = 0.4 kg(0.88lbs) : Ⓒ
▶ Revised the total additional charging amount = Ⓑ + Ⓒ = 2kg (4.41lbs) + 0.4 kg(0.88lbs)
= 2.4 kg(5.29lbs)
+=
Total amount(kg)
AB
+
C
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